Question

the 4th term and 10th term of a.p. are 13 and 25 . find a.p.​

Answer 1

Step-by-step explanation:

By elimination method,

a+3d=13

a+9d=25

________

-6d=-12

d=2

put d=0,

a+3(2)=13

a+6=13

a=6

A.P. is 6,8,10,12.........

Answer 2

Answer:

A4=13

A5=25

subtract a5-a4,

a+4d-(a+3d)=a+4d-a-3d

25-13 =d

so,d=12

keep th d value in any of the equation, You will get the value of a,

a+4d=25

a+48=25

a= -23

so,

the Ap is -23, -11, 1.............

Just keep adding the common difference