Question

The 4th term and 7th term of a GP is 18 and 729/8. Is 59049/128 a term in the GP? If so, what is the term?

Answer 1

Step-by-step explanation:

Hi , there !!!

4th term of GP is = ar³ = 1/ 27

7th term of GP is ar^6= 1/729

dividing both

we get

r³ = 27

r = 3

ar³ = 1/ 27

a =1/ 81

first nth term will be

ar ^ n -1

=> 1/ 81 × 3 ^ n-1

=> 1 / 27 ^ n-1

hope it help you

thanks !!