the 4th term from the end of an A.P. : -11, -8, -5, ........49 is
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Step-by-step explanation:
- given a=-11 and a2=-8
- and also last term or an=49
- now d=a2-a1=-8-(-11)=-8+11=3
- according to question
- an=a+(n-1)d
- 49=-11+(n-1)3
- 49+11=(n-1)3
- since, n-1=60/3
- n=20+1=21
- hence number of term are 21
- so 4th term from the term is 18th term
- now again according to question
- a18=a+(n-1)d
- a18=-11+(18-1)3
- a18=-11+17×3
- a18=-11+51
- a18=40
- hence the 4th term of this ap from end is 40.....
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