The 4th term from the end of an ap -10,-7,-4...... 48 is
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The 4th term from the end of an ap -10,-7,-4...... 47 is 35
As the sequence is an ap,
The first term, a is -10,
common difference, d is = -7 - (-10) = -7 + 10 = 3
nth term in an AP is = a + (n-1)d
47 is the:
-10 + (n-1)*3 = 47
⇒ -10 + 3n - 3 = 47
⇒ 3n = 60
⇒ n = 20
So, 47 is the 20th term.
4th term from the end is the 16th term, which is
a + (16-1)d
= -10 + 15*3
= -10 + 45
= 35
35 is the required term.
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