Question

the 4th term from the end of the a.p -11,-8,-5......49 is

Answer 1

d= -8-(-11) = 11-8 = 3, a= -11, last term is 49 ==> a+(n-1)d = 49 ==> -11 + (n-1)3 = 49

==> (n-1)3 = 60 ==> n-1 = 20 ==> n=21

number of terms is 21. 4th term from last is (21-4+1)th from the beginning.

we need to find 18th term from the beginning.

18th term is a+17d = -11 + 17(3) = -11 +51 = 40

Answer 2

Hope this helps ....plz mark as brainliest..!