The 4th term from the end of the AP: –11, –8, –5, ..., 49 is
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Answer:
Step-by-step explanation:
to find the term from the last make the sequence as reverse like
49,46,43,....-5,-8,-11
now find the 4th term from starting
given
a=49
d=-3
T4=a+3d
=49+3(-3)
=49-9
=40
hence The 4th term from the end of the AP: –11, –8, –5, ..., 49 is 40
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