The 4th term of a G. P. is 16 and the 7th term is 128. find the first term and common ratio of the series.
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Heya!!
Here's your answer!!
Let a be the first term and r be the common ratio of the given G.P.
therefore,
T4 = 16 and T7 = 128
=> ar³ = 16 .... (i)
and ar⁶ = 128. ....(ii)
Dividing equation (ii) by equation (i), we get
ar⁶/ar³ = 128/16
= r³ = 8
= r = 2
therefore,
From equation (i), a× 2³ = 16
= a= 16/8 = 2
a = 2,
r= 2.
Glad help you,
it's helps you,
thanks.
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