The 4th term of a G.P. is square of its second term,and the first term is -3. Find its 7th term.
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Hi!
The first term, a of the G.P. is given as –3.
The nth term of the G.P. is given by an = arn – 1
∴Second term, a2 = ar = –3r
4th term, a4 = ar3 = –3r3
It is given that, –3r3 = (–3r)2
∴–3r3 = 9r2
⇒ r = –3
Thus, 7th term, a7 = ar6 = –3(–3)6 = –2187
Hope! You got the answer.
Cheers!
The first term, a of the G.P. is given as –3.
The nth term of the G.P. is given by an = arn – 1
∴Second term, a2 = ar = –3r
4th term, a4 = ar3 = –3r3
It is given that, –3r3 = (–3r)2
∴–3r3 = 9r2
⇒ r = –3
Thus, 7th term, a7 = ar6 = –3(–3)6 = –2187
Hope! You got the answer.
Cheers!
Answered by
3
Heya....
First given term of G.P is -3
The nth term is an= arn-1
So second term = a2 = ar = -3r
4th term is a4= ar3 = -3r3
Given is -3r3= ar2
So r = -3
Thus.. 7th term will be...
a7 = ar6 = -3(-3)6= -2187....
## Good luck !!!
First given term of G.P is -3
The nth term is an= arn-1
So second term = a2 = ar = -3r
4th term is a4= ar3 = -3r3
Given is -3r3= ar2
So r = -3
Thus.. 7th term will be...
a7 = ar6 = -3(-3)6= -2187....
## Good luck !!!
rajsawner26:
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