The 4th term of a G.P. is square of its second term,and the first term is -3. Find its 7th term.
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✔✔ The first term, a of the G.P is given as -3
✔✔ The nth term of the G.P. is given by an = arn – 1
✔✔ ∴Second term, a2 = ar = –3r
4th term, a4 = ar3 = –3r3
✔✔ It is given that, –3r3 = (–3r)2
∴–3r3 = 9r2
✔✔ ⇒ r = –3
✔✔ Thus, 7th term, a7 = ar6 = –3(–3)6 = –2187
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The first term, a of the G.P is given as -3
The nth term of the G.P. is given by an = arn – 1
∴Second term, a2 = ar = –3r
4th term, a4 = ar3 = –3r3
It is given that, –3r3 = (–3r)2
∴–3r3 = 9r2
⇒ r = –3
Thus, 7th term, a7 = ar6 = –3(–3)6 = –2187
HOPE IT HELPS ✌
The nth term of the G.P. is given by an = arn – 1
∴Second term, a2 = ar = –3r
4th term, a4 = ar3 = –3r3
It is given that, –3r3 = (–3r)2
∴–3r3 = 9r2
⇒ r = –3
Thus, 7th term, a7 = ar6 = –3(–3)6 = –2187
HOPE IT HELPS ✌
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