The 4th term of an A.P is equal to 3 times the first term and the 7th ter
exceeds twice the 3rd term by 1. Find the A.P
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Answered by
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Step-by-step explanation:
Given: In an AP:
A4=3(a)
a+3d=3a
3d=3a-a=2a
0=2a-3d----(1)
a7-2(a3)=1
a+6d-2(a+2d)=1
a+6d-2a-4d=1
(-a+2d=1)2
-2a+4d=2----(2)
By Elimination method:
2a-3d=0
-2a+4d=2
d=2-----(3)
(3) in (1):
2a-3(2)=0
2a=6
a=3.
Therefore the AP is 3,5,7,9..............
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0
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