Question

The 4th term of an A.P is ten times the first. Prove that the 6th term is four times as great as the second term.​

Answer 1

Answer:

Given

(t4)10=t1

To Prove : 4(t6) =t2

t4=a+(4-1)d=>a+3d

t1=a+(1-1)d=>t1=a

since t1=t4

a=a+5d

5d=0

d=0-----------(1)

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t6=a+(6-1)d=>a+5d

t2=a+(2-1)d=>a+d

Substituting d=0 from 1

t6=>a+5(0)=>a

t2=a+0=>a

Therefore t6 = t2 = a

Answer 2

Answer:

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