the 4th term of an a.p is zero.prove that the 25th term of an a.p is three times it 11th term
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tn=a+(n-1)d
A/Q
a+(4-1)d=0
a+3d=0
a=-3d
again
a+(25-1)d=3(a+(11-1)d)
a+24d=3(a+10d)
a+24d=3a+30d
putting the value of a
-3d+24d=3*-3d+30d
21d=-9d+30d
21d=21d
proved
A/Q
a+(4-1)d=0
a+3d=0
a=-3d
again
a+(25-1)d=3(a+(11-1)d)
a+24d=3(a+10d)
a+24d=3a+30d
putting the value of a
-3d+24d=3*-3d+30d
21d=-9d+30d
21d=21d
proved
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