The 4th term of an A. Pis 14 and 8 term is less than twice the 5 term find the 1st
25 term of A.P.
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Step-by-step explanation:
a+3d=14
a+7d=2(a+4d)
a+7d= 2a+8d
-a=d
a+3×-a=14
a-3a=14
-2a=14
a=-14/2
a=-2
-2+3d=14
3d=16
d=16/3
a+24d= -2+24×16/3
= -2+128
= 126
25term is 126
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