Question

the 4th term of an AP -11,-8,-5.......49 is​

Answer 1

Answer:

1

Step-by-step explanation:

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Answer 2

Question :

The 4th term of an AP -11,-8,-5 ......49 is

To find :

$\large\sf{t_4=?}$

Solution :

$\\ \large\red\bigstar\sf{ the \: sequence \: are \: -11,-8,-8....49}$

$\\ \large\bullet\sf{a(first \: term)=-11}$

$\\ \large\bullet\sf{d(common \: difference) =d-a=-8-(-11)=-8+11=3}$

$\\ \large\bullet\sf{t_4 =?}$

$\\ \large\implies\sf{tn=a+(n-1)d}$

$\\ \large\implies\sf{t_4=-11+(4-1) \times 3}$

$\\ \large\implies\sf{t_4=-11+3 \times 3}$

$\\ \large\implies\sf{t_4=-11+9}$

$\\ \large\implies\sf{t_4=-2}$

$\\ \large\red\bigstar\boxed{\sf{t_4=-2}}$

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