Question

The 4th term of an AP is 0 . Prove that it's 25th term is triple is 18th term.

Answer 1

Let the first term of an AP is a and common difference is d

4th term = a + ( 4 - 1 )d = a + 3d = 0

a = - 3d

now,

t25 = a + ( 25 -1 ) d = 24d - 3d = 21d

t18 = a + ( 18 -1 ) d = 17d - 3d = 14d


hence it's prove that

t25 = 3*t18

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Answer 2

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