Question

The 4th term of an AP is equal to 3 times of the first term
and the 7th team exceeds
the 3rd term by 1 . find first term and the common difference​

Answer 1

Step-by-step explanation:

A(4) = 3A(1)

a + 3d = 3a

2a = 3d

a = 3d/2

A(7) = A(3) + 1

a + 6d = a + 2d + 1

4d = 1

d = 1/4

a = 3/2 * 1/4 = 3/8

Answer 2

Answer:

d= $\frac{1}{4}$, a= $\frac{3}{8}$.

Step-by-step explanation:

Given,

$a_{4}$=3a

=a+3d=3a

2a=3d ------->(i)

$a_{7}$=$a_{3}$+1

a+6d=a+2d+1

4d=1

d= $\frac{1}{4}$

putting value of d in (i)

2a=3($\frac{1}{4}$)

2a=$\frac{3}{4}$

a= $\frac{3}{8}$

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