the 4th term of an ap is equal to 3 times the 1st term and the 7th term exceeds twice the 3rd term by 1 then first term a and common difference d are
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common difference= 2
Step-by-step explanation:
a4 = 3a1
a7 - 2a3 = 1
a + 3d = 3a
d = ⅔a –––: 1
————
a + 6d - 2( a + 2d ) = 1
⅓ × a = 1
a = 3
By substituting a value in equation 1
We get d = 2
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