The 4th term of an ap is equal to 3 times the 1st term and the 7th term exeeds twice the 3ed term by 1 find the ap
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Answered by
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4th term= 3a
a+3d=3a
a=3d/2
7th term=2(a+2d)+1
a+6d=2(a+2d)+1
a+6d=2a+4d+1
Applying value of a
2×3d/2+4d+1=15d/2
7d+1=15d/2
d=2
a=6/2=3
Ap= 3,5,7,9,..
Answered by
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Answer:
Step-by-step explanation:
4th term= 3a
a+3d=3a
a=3d/2
7th term=2(a+2d)+1
a+6d=2(a+2d)+1
a+6d=2a+4d+1
Applying value of a
2×3d/2+4d+1=15d/2
7d+1=15d/2
d=2
a=6/2=3
Ap= 3,5,7,9,..
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