The 4th term of an ap is equal to 3 times the first term and 7th term exceeds the third term by one. find the AP
gouribmanoj:
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let the first term a
then the fifth term =a+3d
according to question =a+3d =3a
=: 3d =3a-a
=: 3d =2a
we have also given a+6d =a+2d +1
=: a-a +6d-2d =1
=: 4d =1
=: d=1/4
put in 3d =2a
3×1/4 = 2a
3/4×2 =a
3/8 = a
So the AP is 3/8,3/8 +1/4,3/8 +2×1/4..........
then the fifth term =a+3d
according to question =a+3d =3a
=: 3d =3a-a
=: 3d =2a
we have also given a+6d =a+2d +1
=: a-a +6d-2d =1
=: 4d =1
=: d=1/4
put in 3d =2a
3×1/4 = 2a
3/4×2 =a
3/8 = a
So the AP is 3/8,3/8 +1/4,3/8 +2×1/4..........
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