Question

the 4th term of an ap is equal to the 3 times of the first termand the 7th term exceeds the 3rd term by 1 find first term and common difference ​

Answer 1

Answer:

Step-by-step explanation: term of an ap is given by a+(n-1)d

4th term is a+3d

1st term of AP is a

7th term is a+6d

3rd term is a+2d

it is given that the 4th term of an ap is equal to the 3 times of the first term

so a+3d =3a

or      2a=3d    (1)

also the 7th term exceeds the 3rd term by 1

   a+6d -(a+2d)=1

     a+6d-a-2d=1

      4d=1

or d=1/4

put d=1/4 in (1)

2a=3(1/4)

or a=3/8

hope it helps