The 4th term of an Ap is three times the first and the 7th term exceeds twice the third term by 1 .find the first term and common difference
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Answered by
5
a+3d=3a
3d=2a
d=2/3a
a+6d=2 (a+3d)+1 =3a+1
a+2/3a×6=3a+1
2a=1
a=1/2
d=1/3
3d=2a
d=2/3a
a+6d=2 (a+3d)+1 =3a+1
a+2/3a×6=3a+1
2a=1
a=1/2
d=1/3
Answered by
3
a+6d=2 (a+3d)+1 =3a+1
a+2/3a×6=3a+1
2a=1
a=1/2
d=1/3
a+2/3a×6=3a+1
2a=1
a=1/2
d=1/3
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