The 4th term of an AP is Zero. Prove that the 25th Term of the AP is 3 times its 11th Term
Answers
Answered by
0
Step-by-step explanation:
4th term = a + 3d = 0
3d = 0 - a = 0
d = 0/3 = 0
so, a + 3(0) = 0
a + 0 = 0
a = 0
25th term = 3 × 11th term
a + 24d = 3 × (a + 10d)
0 + 24(0) = 3 × [ 0 + 10(0) ]
0 + 0 = 3 × (0 + 0)
0 = 3 × 0
0 = 0
Hence Proved.
Hope it helps u !!!!!!!!!
Similar questions