the 4th term of an AP is zero .prove that the 25th term of the AP is three times its 11th term...
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Given= T4=0
To prove = T25=3×T11
Proof= a+3d=0
=> So a=-3d
And, a+24d=3×(a+10d)
Putting a=-3d in above equation
-3d+24d=3(-3d+10d)
=> 21d=21d
LHS=RHS
HENCE PROVED
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