the 4th term of an AP,three times the 1st term and the 7thterm exceeds twice the 3rd term by 1
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Answer:
a= 3/5 , d = 2/5 .
Step-by-step explanation:
4th term is three times the 1st term
a+3d = 3a
=> 3a-a = 3d
=> 2a= 3d
7th term exceeds twice the 3rd term by 1
a+6d = 2(a+2d) +1
=> a-2a = 1-6d+2d
=> a= 4d -1
=> 3/2 d= 4d -1
=> 4d - 3/2 d = 1
=> 5/2 d = 1
=> d = 2/5
a= 3/2 * 2/5 = 3/5 .
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