Question

the 4th term of an arithmetic sequence 12 and 10th term is 30 find the 37th term​

Answer 1

Answer:

Step-by-step explanation:

a+3d=12

a+9d=30

so calculating from this we get d= 3

and a =3

so 37th term= 3+(37-1)3

=3+36*3

=111