the 4th term of AP is equal to 3 times the first term and the 7th term exceeds twice the third term by 1.find the first term and the common difference.
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a+3d=3(a+d)
a+3d=3a+3d
a-3a=0
-2a=0
a=0
a+6d-2(a+2d)=1
a+6d-2a+4d=1
-a+10d=1
put a=0
0+10d=1
d=1/10
hope it helps....
a+3d=3a+3d
a-3a=0
-2a=0
a=0
a+6d-2(a+2d)=1
a+6d-2a+4d=1
-a+10d=1
put a=0
0+10d=1
d=1/10
hope it helps....
Answered by
2
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