the 4th term of arthematical progression of 5,8,11 is
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an= a+(n-1) d
a4=5+(4-1) 3
a4=5+(3) (3)
a4=5+9
a4=14
The 4th term is 14
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Step-by-step explanation:
The 4 term of arithmetical progression is 14
A1= 5, a2 = 8,a3= 11
firstly we find common difference
a2-a1
8-5
= 3
A4 = a+3d
5 +3×3
5+ 9
14
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