The 4th term of gp is 16 and the 7th term is 128. Find the first term and the common ratio
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Step-by-step explain
let first term be a
common ratio be b
ar^3 = 16
ar^6 = 128
deviding both equations
we get r^3 = 2^3
hence r = 2
ar^3 = 16
hence a = 2
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