Math, asked by mohankhan22072036, 1 year ago

The 4th vertex D of a parallelogram ABCD whose three vertices are A ( -2 , 3 ), B ( 6 , 7 ), C ( 10 , 3 ) is:
(a) ( 0 , 1 )
(b) ( 2 , -1 )
(c) ( -1 , 0 )
(d) ( 1 , 0 ) ​

Answers

Answered by kerubhaudhage
4

Answer:

4+x/2 '3+y /2 =7/2'8/2

4+x / 2 '=7/2

4+x=7 and 3+x/ 2 =8/2

x=3 and 3+y =8

x=3 and y=5

d is (3,5)

Answered by manoj4271609k
1

Answer:

d is 3,5

Step-by-step explanation:

thanks please help others

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