Hindi, asked by abhishekkadamfymeb, 22 days ago

The 5 is the frequency of _________observation from the data 1.2, 1.21,1.5 ,1.2, 1.5, 1.4, 1.41 ,1.21, 1.5, 1.2, 1.8, 1.7, 1.8, 1.81, 1.4, 1.5, 1.2, 1.6, 1.7, 1.5, 1.8, 1.31 ,1.2, 1.2. (1 Point)

Answers

Answered by ramyarajasekar8thg
0

Explanation:

Definition: the aggregate (sum) of all the data values divided by the number of data points.

Where µ represents the mean of a population, and ∑ represents the sum of all the data values, and N represents the number of data values. If the data set refers to a sample (part of a population), the calculation remains the same but the symbols are different. This is important because it indicates to anyone whether we are dealing with a population or a sample. A data set always has a mean and it is unique.

Find the Mean value

To find the Mean value, divide the Sum by the number of values.

In our case, we found in the previous step that the sum is -9.4 and we can count the 8 values so:

Mean = -9.4/8 = -1.175    

Median

Definition: the middle (center) value of a data set after the data has been arranged from low to high value. That is, 50% of the data values are below the median value and 50% of the data values are above the median value. A simple formula can be applied. The position (P) of the median is: P=. If n the number of data points is odd, the median value is one of the data points. If n is even, then the median is the average of the data values directly below and above the position calculation. A data set always has a median and it is unique.

Find the Median value

To find the Median value, we begin by sorting Or arranging our numbers In ascending Or descending order.

-1.8,-1.7,-1.6,-1.5,-1.4,-1.3,-1.2,1.1

Having an even (8) number of values, the median is the midway point between the two middle numbers.

In our case the two middle numbers are -1.5 and -1.4

(-1.5+-1.4)/2

Median=-1.45    (In words: one && 45/100)

Range

The numerical difference between the maximum and minimum values of a data set.

R = maximum – minimum values

Find the Range

Using our sorted list of numbers

-1.8,-1.7,-1.6,-1.5,-1.4,-1.3,-1.2,1.1

we subtract the first (smallest/min) from the last (biggest/max)

Range = 1.1--1.8 = 2.9

Variance

Definition: the average of the squared differences from the mean of a data set. It is a measure of the spread of a data set from the mean.

In probability theory and statistics, variance measures how far a set of numbers is spread out. A variance of zero indicates that all the values are identical.

Find the Variance

To calculate the variance follow these steps:

Work out the Mean (the simple average of the numbers). We did this above and found if to be -1.175

Now, for each number: subtract the Mean and square the result (the squared difference).

(-1.8--1.18)2=0.39

(-1.7--1.18)2=0.28

(-1.6--1.18)2=0.18

(-1.5--1.18)2=0.11

(-1.4--1.18)2=0.05

(-1.3--1.18)2=0.02

(-1.2--1.18)2=0

(1.1--1.18)2=5.18

Find the average of those squared differences.

0+0.39=0.39

0.39+0.28=0.67

0.67+0.18=0.85

0.85+0.11=0.95

0.95+0.05=1

1+0.02=1.02

1.02+0=1.02

1.02+5.18=6.2

The Sum of the 7 squared differences is 6.2

We can now calculate the Variance as 6.2/7  =  0.89

Standard Deviation

Definition: The square root of the variance. It measures the spread of the data set from the mean. Note that the unit measure of the standard deviation is the same as the data se. That is, if the data is in feet the standard deviation is also in feet. This is not true for the variance.

In statistics, the standard deviation (SD, also represented by the Greek letter sigma, σ) is a measure that is used to quantify the amount of variation or dispersion of a set of data values.

Standard Deviation is the positive square root of the Variance

√(0.89)=0.94

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