Question

The 5 term of an arithmetic progression is equal to 1 and the 31 is equal to -77 Find the 10th term of this
arithmetic progression
10 term​

Answer 1

Answer:

-14

Step-by-step explanation:

given t5 = 1

t31 = -77

Formula : tn = a+(n-1)d

t5=1 ––––> a+4d = 1

t31 = -77 ––––> a+ 30d = -77

subtracting both we get ,

4d-30d = 1+77

-26d = 78

d= -3

Put d = -3 in a+4d = 1

a-12 = 1

a= 13

t10 = a+(10-1)d = a+9d = 13+9(-3)

= 13-27 = -14

Answer 2

Answer:

a5 = 1

a31 =-77

a+4d  = 1 ..........(1)

a+30d=-77

By elimination method

-26d=78

     d=-3

 Sub d in (1)

a -12 =1

a = 13

a10 = a + 9d

a10 = 13+-27

a10=-14

Hope this helps you!!!!