Question

The 5 th term in the expansion of (x^(2)+2y)^(5) will be​

Answer 1

Answer:

Step-by-step explanation:

Expand the expression (2/x – x/2)5

Answer:

By using Binomial Theorem, the expression (x + 1/x)6 can be expanded as

(x + 1/x)6 = 6C0 (x)6 + 6C1 (x)5 (1/x) + 6C2 (x)4 (1/x)2 + 6C3 (x)3 (1/x)4 + 6C4 (x)2 (1/x)4 + 6C5 (x) (1/x)5

                     + 6C6 (1/x)6  

                   = x6 + 6(x)5(1/x) + 14(x)4(1/x2) + 20(x)3(1/x3) + 15(x)2(1/x4) + 6(x)(1/x5) + 1/x6

                   = x6 + 6x4 + 15x2 + 20 + 15/x2 + 6/x4 + 1/x6