Question

The 5 th term of an AP exceeds its 12 th term by 14 .if it's 7 th term is 4 ,find the AP

Answer 1

Let the first term of AP be" a" and it's common difference be "d".

According to this question,

T5+T12=14

a+4d+a+11d=14

2a+15d=14________[1]

Given,

a+6d=4________[2]

On multiplying [2] by 2 and subtracting it from [1], we get,

3d =6

So, d=2

Now, from [2], we get,

a=-8

Thus required AP is...a, a+d,a+2d...

=-8 -6,-4,-2....

Hope it helps you......