the 50kg homogeneous smooth rests on the 30° incline A and B bears against the smooth vertical wall B .calculated the contact forcses at A and B?
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et the contact force acting on point A be A newtons and acting on point B be B newtons.then by resolving forces along horizontal and vertical directions
A cos 30=mg
A sin 30=B
A=50*9.8/.866=565.81 Newton
B=565.81*.5=282.90 Newton
A cos 30=mg
A sin 30=B
A=50*9.8/.866=565.81 Newton
B=565.81*.5=282.90 Newton
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1
answer for force on A is given in the picture above.
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