The 54th term of an ap is -61 and its 4th term is 64 find its 23rd term
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Let the 54th term = a+53d= -61
and 4th term= a+3d= 64
a+53d= -61
a+3d= 64
Using elimination method
50d= -125
d= -5/2
Now put the value of d in any of the equation you get the value of a.
a= 143
Now, you need to find the 23rd term
I.e
a+22d= 143+22(-5/2)
143-55
88
Hence, the 23rd term of this A.P. is 88
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