The 5th and 10th terms of an AP are -12 and -27 find the AP and 15th term
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Answer:
Step-by-step explanation:
tn=a+(n-1)d
t5=a+4d
a+4d=-12 ..(1)
t10=a+9d
a+9d=-27...(2)
subtracting (1) from(2)
a+9d=-27
-a-4d=+12
=5d=-15
d=-5
a+4d=-12
a+4*-5=-12
a=-12+20=8
Ap is: 8,3,-2,.....
t15=8+14*-5=8-70=-62
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