Question

the 5th and 12th term of AP are 52 and 24 respectively then find first 3 terms of that AP. *​

Answer 1

Given:

5th term=52 ,12th term-24

a5=a+4d-----1

a12=a+11d-----2

Subtract 1&2

d=-4

a5=a+4d

52=a+4×-4

a=52+16=68

a2=68+-4=64

a3=68+2×-4=60

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Answer 2

Step-by-step explanation:

a= 1st term

d= diffrence

Tn = a+(n-1)×d

T5 = 52

=> a+4d = 52 -->i)

T12 = 24

=> a+11d = 24 -->ii)

SUBTRACTING i) and ii)

(a+4d) - (a+11d) =52 - 24

=> -7d = 28

=> d = -( 28/7 )

=> d = -4

PUTTING d=-4 ,in i)

a+4×(-4) = 52

=> a-16 = 52

=> a = 52+16

=> a = 68

SO, T3= 68+( 3-1 )×(-4)

= 68-8

= 60 ANSWER

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