Question

The 5th term & 21 st team
of a series in A.P are
10 to 42
respectively. Find the 31 st term​

Answer 1

Answer:

61

Step-by-step explanation:

first term is a and the 5th term be a + 4d 21st term be a + 20d

a + 4d = 10

a + 20d = 42

solving these two equations simultaneously

a = 1 and d = 2

so the 31st term is a +30d = 1 + 30*2 = 61

Answer 2

Answer:

31st term=62

Step-by-step explanation:

given,a+4d=10

a+20d=42

by subtracting the above equations we get,

-16d=-32

therefore,d=2

so,a=2

so,31st term=a+30d

= 2+30×2

=62

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