The 5th term of an A.P tn=7n-3is
Answers
Answer:
t5 = 7×5 - 3 = 35-3 = 32 this is the solution
EXPLANATION.
⇒ Tₙ = 7n - 3.
As we know that,
Put the value of n = 1 in the equation, we get.
⇒ 7(1) - 3.
⇒ 7 - 3 = 4.
Put the value of n = 2 in the equation, we get.
⇒ 7(2) - 3.
⇒ 14 - 3 = 11.
Put the value of n = 3 in the equation, we get.
⇒ 7(3) - 3.
⇒ 21 - 3 = 18.
Put the value of n = 4 in the equation, we get.
⇒ 7(4) - 3.
⇒ 28 - 3 = 25.
Series = 4, 11, 18, 25, . . . . .
First term = a = 4.
Common difference = d = b - a = c - b.
Common difference = d = 11 - 4 = 7.
To find 5th term of an A.P.
As we know that,
General term of an A.P.
⇒ Tₙ = a + (n - 1)d.
⇒ T₅ = a + (5 - 1)d.
⇒ T₅ = a + 4d.
Put the values in the equation, we get.
⇒ T₅ = 4 + 4(7).
⇒ T₅ = 4 + 28.
⇒ T₅ = 32.
MORE INFORMATION.
Supposition of terms of an A.P.
(1) = Three terms as : a - d, a, a + d.
(2) = Four terms as : a - 3d, a - d, a + d, a + 3d.
(3) = Five terms as : a - 2d, a - d, a, a + d, a + 2d.