Question

The 5th term of an AP is 13 and the 1st term is -3. Find the 6th term and the sum of the first
12 terms.

Answer 1

Answer:

Here is the your answer

Answer 2

Answer:

a6 = 17

Sum = 228

Step-by-step explanation:

a5 = 13

a = -3

a5 = a + 4d

13 = -3 + 4d

13 + 3 = 4d

16 = 4d

16/4 = d

d = 4

a6 = a + 5d

a6 = -3 + 5(4)

a6 = -3 + 20

a6 = 17

a = -3

a2 = a + d = -3 + 4 = 1

a3 = a2 + d = 1 + 4 = 5

a4 = a3 + d = 5 + 4 = 9

a5 = a3 + d = 9 + 4 = 13

a6 = 17

a7 = a6 + d = 17 + 4 = 21

a8 = a7 + d = 21 + 4 = 25

a9 = a8 + d = 25 + 4 = 29

a10 = a9 + d = 29 + 4 = 33

a11 = a10 + d = 33 + 4 = 37

a12 = a11 + d = 37 + 4 = 41

Adding all 12 terms,

-3 + 1 + 5 + 9 + 13 + 17 + 21 + 25 + 29 + 33 + 37 + 41

= 228

Here is your answer

Hope it helps..