The 5th term of an AP is 13and the 1st term is -3. Find the 6th term
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5th term = a+4d ---------1
and , a=-3
so, put the value of a in eqn 1
we get ,
-3+4d=13
4d=13+3
d =16/4
d =4
then,
An = a+(n-1)d
A6= -3+(6-1)×4
A6=-3+20
A6= 17
So, the 6th term ofAP is 17 .
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