Question

the 5th term of an arithmetic sequence 38 and the 9th term is 66.wthat is the 25 th term
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Answer 1

Answer:

ok I will explain

Step-by-step explanation:

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Answer 2

Answer:

According to the given condition,

t5=38

t9=66

To find:-25th term=?

1) tn=a+(n-1)d

t5=a+(5-1)d

38=a+4d

a+4d=38-(1)

2) tn=a+(n-1)d

t9=a+(9-1)d

66=a+8d

a+8d=66

now,

subtracting equation 1 and 2 we get,

a+8d=66

-a-4d= -38

_________

4d= 28

d=28/4

d=7

put d=7 in equation 1

a+4d=38

a+4(7)=38

a+28=38

a=38-28

a=10

now t25=?

tn=a+(n-1)d

t25=10+(25-1)7

t25=10+24x7

t25=10+168

t25=178

hope it help you buddy