Question

The 5th term of an arithmetic sequence is 38 and the
9th term is 66 what is its 25th term​

Answer 1

Answer:T5=38

a+(n-1)d=38

a+4d=38--------------(Equation 1)

Similarly, a+8d=66----(Equation 2)

Adding 1 and 2,

We get d=7 and a=10.

Hence,T25=a+(24-1)d

T25=10+25(7)

T25=185(answer)

Step-by-step explanation: