Question

The 5th term of an arthmetic sequence is 32 and 9th term is 66 what is the 25th

Answer 1

25th term is equal to 178.

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Answer 2

Step-by-step explanation:

(a is used to denote terms)

Given: a5=a+4d=32---------(1)

a9=a+8d=66----(2)

To find: a25=?

(2)-(1)

a+8d-(a+4d)=66-32

a+8d-a-4d=34

4d=34

d=17/2----(3(

Now, (3) in (1)

a+4(17/2)=32

a+34=32

a=32-34=-2

a25= a+24d

=-2+24(17/2)

=-2+12(17)

=-2+204

=202.