Question

The 6-digit number 2ABCDE is multiplied by 3 and the result is the 6-digit numbe
ABCDE2. What is the sum of the digits of this number?
(C) 30
(A) 24
(D) 33
(B) 27
(E) 36​

Answer 1

Given :- The 6-digit number 2ABCDE is multiplied by 3 and the result is the 6-digit numbe ABCDE2. What is the sum of the digits of this number ?

(C) 30

(A) 24

(D) 33

(B) 27

(E) 36

Answer :-

2ABCDE

×3

ABCDE2

Starting from right we get,

• E * 3 = 2 in last
• E = 4
• so, 4 * 3 = 12 (1 carry)

now,

2ABCD4

×3

ABCD42

we get,

• D * 3 + 1 = 4 in last
• D * 3 = 4 - 1 = 3
• D = 1 .

putting this value also,

2ABC14

×3

ABC142

we get,

• 3 * C = 1 in last
• C = 7
• 3 * 7 = 21 then 2 is carry .

putting this value also,

2AB714

×3

AB7142

we get,

• 3 * B + 2 = 7
• 3 * B = 5
• B = 5
• 1 carry { 3 * 5 = 15 }

putting this value also,

2A5714

×3

A57142

we get,

• A * 3 + 1 = 5
• A * 3 = 5 - 1 = 4
• A = 8

finally we get,

285714

×3

857142

therefore,

→ 2 + A + B + C + D + E

→ 2 + 8 + 5 + 7 + 1 + 4

→ 27 (B) (Ans.)

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