Question

the 6 disinct interger whose sum is 7​

Answer 1

Answer:

-4/3 , -1/3 , 2/3 , 5/3 , 8/3 , 11/3

Step-by-step explanation:

let's take the 6 integers as :

x , x+1 , x+2 , x+3 , x+4 , x+5

x + x+1 + x+2 + x+3 + x+4 + x+5 = 7

6x + 15 = 7

6x = 7-15

6x = -8

x = -8/6 = -4/3

x + 1 = -4/3 + 1 = -1/3

x + 2 = 2/3

x + 3 = 5/3

x + 4 = 8/3

x + 5 = 11/3