Math, asked by shersingh95407p4ztq6, 1 year ago

the 6 term of an ap is zero prove that its 31st term is 5 times the 11 term

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Answered by sonu579
1
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Answered by ak3057955
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MahichhabraAmbitious

given 6th term is zero

so

a + (6-1)d = 0

a + 5d = 0

so a = -5d

now

31st term is

a + (31-1)d

a + 30d..........(1)

also

11 th term is

a +(11-1)d

a + 10d

so 5 times 11 term is

5a + 50d.........(2)

on comparing with 1 we want only single a so we convert the remaining 4a into d

so

a + 4a + 50d

as

a = -5d

a + 4(-5d) + 50d

a - 20d + 50d

a + 30d

31st term

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