the 6 term of an ap is zero prove that the 30 term of an ap is 3 times its 10 term
Dhruv00:
Are u sure that t30 = 3× t10
yes definetly
i think i am getting an wrong answer in this Q
but it is coming that t30= 6* t10
plz recheck the Q
but in my Q paper it is clearly printed that its three times its 10 term
sum 10 terms of only 10th term
of*,or*
i dont know any thing about this Q hoe to solve this?
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use formula,
Tn = a + (n -1)d
where a is the first term and d is the common difference of AP.
T6 =0
a + (6 -1)d =0
a + 5d =0
a = -5d
now,
T30. = 3T10
LHS = a + (30 - 1)d = a + 29d = -5d +29d =24d
RHS = 3(a + 9d ). = 3(-5d + 9d) = 12d
LHS ≠ RHS
something wrong in question.
Tn = a + (n -1)d
where a is the first term and d is the common difference of AP.
T6 =0
a + (6 -1)d =0
a + 5d =0
a = -5d
now,
T30. = 3T10
LHS = a + (30 - 1)d = a + 29d = -5d +29d =24d
RHS = 3(a + 9d ). = 3(-5d + 9d) = 12d
LHS ≠ RHS
something wrong in question.
this q is same as in my q paper
something wrong dear , because not possible
okk then i will talk to my sir about this well thanks for your kind concern to my Q which is proved wrong right now
okay
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