Question

The 6 times of a fraction is 11 more than the seven times the order of that fraction. What is that different

Answer 1

Answer:

please complete the question bro or sis

Answer 2

The two different fraction are $\dfrac{1}{-2}$  ,   $\dfrac{7}{3}$

Step-by-step explanation:

Given as :

The statement is

The 6 times of a fraction is 11 more than the seven times the order of that fraction .

Let The fraction = $\dfrac{1}{y}$

According to question

6 × fraction = 7 × its reciprocal + 11

Or, 6 × $\dfrac{1}{y}$ = 7 × $\dfrac{1}{\dfrac{1}{y} }$  + 11

Or, $\dfrac{6}{y}$ = 7 y + 11

Or, 6 = 7 y² + 11 y

Or, 7 y² + 11 y - 6  = 0

Now solving the quadratic equation by middle term break , we get

∴ 7 y² + 11 y - 6  = 0

Or,  7 y² + 14 y - 3 y - 6  = 0

Or,  7 y ( y + 2 ) - 3 ( y + 2 ) = 0

Or, ( y + 2 ) ( 7 y - 3 ) = 0

Or,  ( y + 2 ) = 0          ( 7 y - 3 ) = 0

So,  y = - 2              ,  y = $\dfrac{3}{7}$

As The fraction = $\dfrac{1}{y}$

For,  y  = - 2

Fraction = $\dfrac{1}{-2}$

For  y = $\dfrac{3}{7}$

Fraction = $\dfrac{1}{\dfrac{1}{\dfrac{3}{7} } }$

i.e  Fraction = $\dfrac{7}{3}$

So, The two different fraction = $\dfrac{1}{-2}$  ,   $\dfrac{7}{3}$

Hence, The two different fraction are $\dfrac{1}{-2}$  ,   $\dfrac{7}{3}$       Answer