Question

The 6th and 10th term of an arithmetic sequence are 36 and 64 respectively. write the first 3 terms of the Arithmetic progress​

Answer 1

Answer:

Here is your answer

Step-by-step explanation:

a6 = 36

so, a + 5d = 36 ___________(1)

a10 = 64

so, a + 9d = 64 ____________(2)

subtract equation (1) from equation (2)

a + 9d - ( a + 5d ) = 64 - 36

a + 9d - a - 5d = 28

9d - 5d = 28

4d = 28

d = 7

put the value if "d" in equation (1)

a + 5d = 36

a + 5×7 = 36

a + 35 = 36

a = 36 - 35

a = 1

first 3 terms __ a , a+d , a+2d

1 , 8 , 15

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